What is the integral from 2 to 6 of (2x^3-2x-3) ?

The integral from 2 to 6 of (2x^3-2x-3) is 596

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 2 to 6 of (2x^3-2x-3)

\int_{2}^{6} (2 x^{3} - 2 x - 3) d x

596

Solution steps

\int_{2}^{6} 2 x^{3} - 2 x - 3 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{2}^{6} 2 x^{3} d x - \int_{2}^{6} 2 x d x - \int_{2}^{6} 3 d x

\int_{2}^{6} 2 x^{3} d x = 640

\int_{2}^{6} 2 x d x = 32

\int_{2}^{6} 3 d x = 12

= 640 - 32 - 12

Simplify

= 596

\int_{0}^{\frac{1}{2}} x \cdot arcsin (x) d x

\int_{0}^{\frac{π}{2}} 1 - cos (2 x) d x

\int_{0}^{t} t^{2} d t

\int_{2}^{23} \frac{1}{4 + z ^{2}} d z

\int_{0}^{5} x^{2} - 4 d x

What is the integral from 2 to 6 of (2x^3-2x-3) ?
The integral from 2 to 6 of (2x^3-2x-3) is 596