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Popular >

integral from 0 to 4 of (8x-32)

Solution

\int_{0}^{4} (8 x - 32) d x

Solution

- 64

Solution steps

\int_{0}^{4} 8 x - 32 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} 8 x d x - \int_{0}^{4} 32 d x

\int_{0}^{4} 8 x d x = 64

\int_{0}^{4} 32 d x = 128

= 64 - 128

Simplify

= - 64

Graph

Popular Examples

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\int_{3}^{- 3} (3 r + 2)^{2} d r

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\int_{0}^{8} (16 x - 128) d x

integral from 0 to 2 of x^3sin(x)

\int_{0}^{2} x^{3} sin (x) d x

integral from 0 to 3 of e^{x^2}x

\int_{0}^{3} e^{x^{2}} x d x

integral from 0 to 2 of sqrt(8x)-x^2

\int_{0}^{2} 8 x - x^{2} d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 4 of (8x-32) ?
The integral from 0 to 4 of (8x-32) is -64