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Popular >

integral from-1 to 1 of 3-|x|

Solution

\int_{- 1}^{1} 3 - ∣ x ∣ d x

Solution

5

Solution steps

\int_{- 1}^{1} 3 - ∣ x ∣ d x

Eliminate Absolutes

= \int_{- 1}^{0} 3 - (- x) d x + \int_{0}^{1} 3 - x d x

\int_{- 1}^{0} 3 - (- x) d x = \frac{5}{2}

\int_{0}^{1} 3 - x d x = \frac{5}{2}

= \frac{5}{2} + \frac{5}{2}

Simplify

\frac{5}{2} + \frac{5}{2} : 5

= 5

Graph

Popular Examples

integral from-1 to 0 of 6x^2(2x^3+3)^2

\int_{- 1}^{0} 6 x^{2} (2 x^{3} + 3)^{2} d x

integral from 1 to infinity of x/(x^2+5)

\int_{1}^{\infty} \frac{x}{x ^{2} + 5} d x

integral from 1 to 10 of x*(2(x-1))/(81)

\int_{1}^{10} x \cdot \frac{2 ( x - 1 )}{81} d x

integral from 2sqrt(x) to 5-3x of 2y

\int_{2 x}^{5 - 3 x} 2 y d y

integral from 0 to x^2 of xcos(pix)

\int_{0}^{x^{2}} x cos (π x) d x

Frequently Asked Questions (FAQ)

What is the integral from-1 to 1 of 3-|x| ?
The integral from-1 to 1 of 3-|x| is 5