What is the integral from 0 to sin(θ) of sec^2(y) ?

The integral from 0 to sin(θ) of sec^2(y) is tan(sin(θ))

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integral from 0 to sin(θ) of sec^2(y)

\int_{0}^{s i n (θ)} sec^{2} (y) d y

tan (sin (θ))

Solution steps

\int_{0}^{s i n (θ)} sec^{2} (y) d y

Use the common integral:

\int sec^{2} (y) d y = tan (y)

= [tan (y)]_{0}^{s i n (θ)}

Compute the boundaries:

tan (sin (θ))

= tan (sin (θ))

\int_{- 2}^{\infty} e^{- 3 x} d x

\int_{0}^{\frac{4}{11}} \frac{1}{121 x ^{2} + 16} d x

\int_{1}^{3} \frac{x ^{3} - 1}{x ^{2} - 1} d x

\int_{2}^{7} \frac{8 x}{x ^{2} + 1} d x

\int_{0}^{1} (x - 1)^{3} d x

What is the integral from 0 to sin(θ) of sec^2(y) ?
The integral from 0 to sin(θ) of sec^2(y) is tan(sin(θ))