What is the integral from b to infinity of 1/x ?

The integral from b to infinity of 1/x is diverges

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integral from b to infinity of 1/x

\int_{b}^{\infty} \frac{1}{x} d x

diverges

Solution steps

\int_{b}^{\infty} \frac{1}{x} d x

Compute the indefinite integral:

\int \frac{1}{x} d x = ln ∣ x ∣ + C

Compute the boundaries:

\int_{b}^{\infty} \frac{1}{x} d x =

diverges

= diverges

\int_{0}^{\frac{1}{2}} arcsin (y) d y

\int_{1 - 5 x}^{1} \frac{u ^{3}}{1 + u ^{2}} d u

\int_{1}^{2} 5 x 5 - x^{2} d x

\int_{1}^{5} \frac{1}{1 + x - 1} d x

\int_{- 2}^{2} 1 - x^{2} d x

What is the integral from b to infinity of 1/x ?
The integral from b to infinity of 1/x is diverges