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Popular >

integral from 0 to 1 of (1-y)

Solution

\int_{0}^{1} (1 - y) d y

Solution

\frac{1}{2}

+1

Decimal

0.5

Solution steps

\int_{0}^{1} 1 - y d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} 1 d y - \int_{0}^{1} y d y

\int_{0}^{1} 1 d y = 1

\int_{0}^{1} y d y = \frac{1}{2}

= 1 - \frac{1}{2}

Simplify

1 - \frac{1}{2} : \frac{1}{2}

= \frac{1}{2}

Graph

Popular Examples

integral from 0 to 2pi of 12

\int_{0}^{2 π} 12 d t

integral from 28 to 53 of xsqrt(x^2-784)

\int_{28}^{53} x x^{2} - 784 d x

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\int_{0}^{a} 6 x a^{2} - x^{2} d x

integral from 0 to pi/2 of cos^3(t)

\int_{0}^{\frac{π}{2}} cos^{3} (t) d t

integral from 4 to 8 of z/(sqrt(z^2-15))

\int_{4}^{8} \frac{z}{z ^{2} - 15} d z

Frequently Asked Questions (FAQ)

What is the integral from 0 to 1 of (1-y) ?
The integral from 0 to 1 of (1-y) is 1/2