What is the integral from 2 to 4 of 1/(sqrt(x-2)) ?

The integral from 2 to 4 of 1/(sqrt(x-2)) is 2sqrt(2)

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integral from 2 to 4 of 1/(sqrt(x-2))

\int_{2}^{4} \frac{1}{x - 2} d x

22

Decimal

2.82842 \dots

Solution steps

\int_{2}^{4} \frac{1}{x - 2} d x

Apply u-substitution

: \int_{0}^{2} 2 d u

= \int_{0}^{2} 2 d u

Integral of a constant:

\int a d x = a x

= [2 u]_{0}^{2}

Compute the boundaries:

22

= 22

\int_{2}^{5} (2 + 2 y)^{2} d y

\int_{1}^{5} \frac{x ^{2} + 3}{x} d x

\int_{v^{1}}^{v^{2}} v d v

\int_{\frac{π}{6}}^{\frac{π}{2}} cos (2 x) d x

\int_{- 1}^{2} x^{2} e^{4 x} d x

What is the integral from 2 to 4 of 1/(sqrt(x-2)) ?
The integral from 2 to 4 of 1/(sqrt(x-2)) is 2sqrt(2)