What is the integral from 0 to 2pi of 8 ?

The integral from 0 to 2pi of 8 is 16pi

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integral from 0 to 2pi of 8

\int_{0}^{2 π} 8 d t

16 π

Decimal

50.26548 \dots

Solution steps

\int_{0}^{2 π} 8 d t

Integral of a constant:

\int a d x = a x

= [8 t]_{0}^{2 π}

Compute the boundaries:

16 π

= 16 π

\int_{0}^{1} arccot (x) d x

\int_{1}^{4} x x - 1 d x

\int_{0}^{x} 1 - t^{2} d t

\int_{0}^{2} 2 x + x^{2} - x^{3} d x

\int_{0}^{5} ∣ 1 - x ∣ d x

What is the integral from 0 to 2pi of 8 ?
The integral from 0 to 2pi of 8 is 16pi