What is the integral from 1 to 4 of (x^4+5x^2) ?

The integral from 1 to 4 of (x^4+5x^2) is 1548/5

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integral from 1 to 4 of (x^4+5x^2)

\int_{1}^{4} (x^{4} + 5 x^{2}) d x

\frac{1548}{5}

Decimal

309.6

Solution steps

\int_{1}^{4} x^{4} + 5 x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{4} x^{4} d x + \int_{1}^{4} 5 x^{2} d x

\int_{1}^{4} x^{4} d x = \frac{1023}{5}

\int_{1}^{4} 5 x^{2} d x = 105

= \frac{1023}{5} + 105

Simplify

\frac{1023}{5} + 105 : \frac{1548}{5}

= \frac{1548}{5}

\int_{0}^{2} x^{3} (2 + x^{4})^{3} d x

\int_{0}^{2} 3 x^{3} - 2 x^{2} - e^{x} d x

\int_{0}^{\frac{π}{2}} (1 + sin (x)) d x

\int_{0}^{1} sin (t) d t

\int_{1}^{3} (2 - x)^{2} d x

What is the integral from 1 to 4 of (x^4+5x^2) ?
The integral from 1 to 4 of (x^4+5x^2) is 1548/5