What is the integral from 2 to 5 of c(1+x) ?

The integral from 2 to 5 of c(1+x) is 27/2 c

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integral from 2 to 5 of c(1+x)

\int_{2}^{5} c (1 + x) d x

\frac{27}{2} c

Solution steps

\int_{2}^{5} c (1 + x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= c \cdot \int_{2}^{5} 1 + x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= c (\int_{2}^{5} 1 d x + \int_{2}^{5} x d x)

\int_{2}^{5} 1 d x = 3

\int_{2}^{5} x d x = \frac{21}{2}

= c (3 + \frac{21}{2})

Join

3 + \frac{21}{2} : \frac{27}{2}

= \frac{27}{2} c

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What is the integral from 2 to 5 of c(1+x) ?
The integral from 2 to 5 of c(1+x) is 27/2 c