What is the integral from 0 to 1 of 3+xsqrt(x) ?

The integral from 0 to 1 of 3+xsqrt(x) is 17/5

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integral from 0 to 1 of 3+xsqrt(x)

\int_{0}^{1} 3 + x x d x

\frac{17}{5}

Decimal

3.4

Solution steps

\int_{0}^{1} 3 + x x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} 3 d x + \int_{0}^{1} x x d x

\int_{0}^{1} 3 d x = 3

\int_{0}^{1} x x d x = \frac{2}{5}

= 3 + \frac{2}{5}

Simplify

3 + \frac{2}{5} : \frac{17}{5}

= \frac{17}{5}

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What is the integral from 0 to 1 of 3+xsqrt(x) ?
The integral from 0 to 1 of 3+xsqrt(x) is 17/5