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Popular >

integral from-1 to 1 of 2y^2-2

Solution

\int_{- 1}^{1} 2 y^{2} - 2 d y

Solution

- \frac{8}{3}

+1

Decimal

- 2.66666 \dots

Solution steps

\int_{- 1}^{1} 2 y^{2} - 2 d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} 2 y^{2} d y - \int_{- 1}^{1} 2 d y

\int_{- 1}^{1} 2 y^{2} d y = \frac{4}{3}

\int_{- 1}^{1} 2 d y = 4

= \frac{4}{3} - 4

Simplify

\frac{4}{3} - 4 : - \frac{8}{3}

= - \frac{8}{3}

Graph

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\int_{0}^{1} (x^{3} - 3 x^{2} + 2 x) d x

Frequently Asked Questions (FAQ)

What is the integral from-1 to 1 of 2y^2-2 ?
The integral from-1 to 1 of 2y^2-2 is -8/3