What is the integral from 0 to 2pi of cos(x)sin^3(x) ?

The integral from 0 to 2pi of cos(x)sin^3(x) is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 2pi of cos(x)sin^3(x)

\int_{0}^{2 π} cos (x) sin^{3} (x) d x

0

Solution steps

\int_{0}^{2 π} cos (x) sin^{3} (x) d x

Compute the indefinite integral:

\int cos (x) sin^{3} (x) d x = \frac{sin ^{4} ( x )}{4} + C

Compute the boundaries:

\int_{0}^{2 π} cos (x) sin^{3} (x) d x = 0 - 0

= 0 - 0

Simplify

= 0

\int_{0}^{x} sin (8 t^{2}) d t

\int_{1}^{4} 3 x + x d x

\int_{1}^{\infty} e^{- s t} (1) d t

\int_{- 2}^{0} 6 x^{2} (2 x^{3} + 1)^{2} d x

\int_{1}^{3} 9 ln (x) d x

What is the integral from 0 to 2pi of cos(x)sin^3(x) ?
The integral from 0 to 2pi of cos(x)sin^3(x) is 0