What is the integral from 1 to infinity of 1/(2x^2) ?

The integral from 1 to infinity of 1/(2x^2) is 1/2

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integral from 1 to infinity of 1/(2x^2)

\int_{1}^{\infty} \frac{1}{2 x ^{2}} d x

\frac{1}{2}

Decimal

0.5

Solution steps

\int_{1}^{\infty} \frac{1}{2 x ^{2}} d x

Compute the indefinite integral:

\int \frac{1}{2 x ^{2}} d x = - \frac{1}{2 x} + C

Compute the boundaries:

\int_{1}^{\infty} \frac{1}{2 x ^{2}} d x = 0 - (- \frac{1}{2})

= 0 - (- \frac{1}{2})

Simplify

= \frac{1}{2}

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What is the integral from 1 to infinity of 1/(2x^2) ?
The integral from 1 to infinity of 1/(2x^2) is 1/2