What is the integral from 1 to 9 of 1/(x^2) ?

The integral from 1 to 9 of 1/(x^2) is 8/9

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integral from 1 to 9 of 1/(x^2)

\int_{1}^{9} \frac{1}{x ^{2}} d x

\frac{8}{9}

Decimal

0.88888 \dots

Solution steps

\int_{1}^{9} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{1}^{9}

= [- \frac{1}{x}]_{1}^{9}

Compute the boundaries:

\frac{8}{9}

= \frac{8}{9}

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What is the integral from 1 to 9 of 1/(x^2) ?
The integral from 1 to 9 of 1/(x^2) is 8/9