What is the integral from k to x of 1/(sqrt(t)) ?

The integral from k to x of 1/(sqrt(t)) is 2sqrt(x)-2sqrt(k)

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integral from k to x of 1/(sqrt(t))

\int_{k}^{x} \frac{1}{t} d t

2 x - 2 k

Solution steps

\int_{k}^{x} \frac{1}{t} d t

Apply the Power Rule

: [2 t^{\frac{1}{2}}]_{k}^{x}

= [2 t^{\frac{1}{2}}]_{k}^{x}

Apply radical rule:

a^{\frac{1}{n}} = n a

= [2 t]_{k}^{x}

Compute the boundaries:

2 x - 2 k

= 2 x - 2 k

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What is the integral from k to x of 1/(sqrt(t)) ?
The integral from k to x of 1/(sqrt(t)) is 2sqrt(x)-2sqrt(k)