What is the integral from-pi to 0 of 6x^3 ?

The integral from-pi to 0 of 6x^3 is -(3pi^4)/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-pi to 0 of 6x^3

\int_{- π}^{0} 6 x^{3} d x

- \frac{3 π ^{4}}{2}

Decimal

- 146.11363 \dots

Solution steps

\int_{- π}^{0} 6 x^{3} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int_{- π}^{0} x^{3} d x

Apply the Power Rule

: [\frac{x ^{4}}{4}]_{- π}^{0}

= 6 [\frac{x ^{4}}{4}]_{- π}^{0}

Compute the boundaries:

- \frac{π ^{4}}{4}

= 6 (- \frac{π ^{4}}{4})

Simplify

= - \frac{3 π ^{4}}{2}

\int_{0.25}^{0.6} 5 (1 - y)^{4} d y

\int_{0}^{x} \frac{( 1 - t )}{e ^{t}} d t

\int_{1}^{10} \frac{1}{x - 1} d x

\int_{1}^{3} 2 x ln (x) d x

\int_{0}^{1} t sin (nπ t) d t

What is the integral from-pi to 0 of 6x^3 ?
The integral from-pi to 0 of 6x^3 is -(3pi^4)/2