What is the integral from 0 to 2 of (sqrt(x)+x^2) ?

The integral from 0 to 2 of (sqrt(x)+x^2) is (4sqrt(2))/3+8/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 2 of (sqrt(x)+x^2)

\int_{0}^{2} (x + x^{2}) d x

\frac{4 2}{3} + \frac{8}{3}

Decimal

4.55228 \dots

Solution steps

\int_{0}^{2} x + x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} x d x + \int_{0}^{2} x^{2} d x

\int_{0}^{2} x d x = \frac{4 2}{3}

\int_{0}^{2} x^{2} d x = \frac{8}{3}

= \frac{4 2}{3} + \frac{8}{3}

\int_{1}^{4} 5 x + 2 d x

\int_{0}^{1} (y^{4} + y^{8}) d y

\int_{2}^{7} \frac{10 x}{x ^{2} + 1} d x

\int_{2}^{3} (2 x - 1) d x

\int_{1}^{2} (3 x^{2} + 4 x^{3}) d x

What is the integral from 0 to 2 of (sqrt(x)+x^2) ?
The integral from 0 to 2 of (sqrt(x)+x^2) is (4sqrt(2))/3+8/3