What is the integral from-2 to-1 of x^3 ?

The integral from-2 to-1 of x^3 is -15/4

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integral from-2 to-1 of x^3

\int_{- 2}^{- 1} x^{3} d x

- \frac{15}{4}

Decimal

- 3.75

Solution steps

\int_{- 2}^{- 1} x^{3} d x

Apply the Power Rule

: [\frac{x ^{4}}{4}]_{- 2}^{- 1}

= [\frac{x ^{4}}{4}]_{- 2}^{- 1}

Compute the boundaries:

- \frac{15}{4}

= - \frac{15}{4}

\int_{0}^{1} (x - 1) e^{- x} d x

\int_{0}^{2} 2 - x^{2} d x

\int_{0}^{\frac{π}{2}} 1 - sin (x) d x

\int_{1}^{2} \frac{e ^{\frac{1}{x}}}{x} d x

\int_{2}^{4} e^{x^{2}} d x

What is the integral from-2 to-1 of x^3 ?
The integral from-2 to-1 of x^3 is -15/4