en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 1 of x^2+x^4

Solution

\int_{0}^{1} x^{2} + x^{4} d x

Solution

\frac{8}{15}

+1

Decimal

0.53333 \dots

Solution steps

\int_{0}^{1} x^{2} + x^{4} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} x^{2} d x + \int_{0}^{1} x^{4} d x

\int_{0}^{1} x^{2} d x = \frac{1}{3}

\int_{0}^{1} x^{4} d x = \frac{1}{5}

= \frac{1}{3} + \frac{1}{5}

Simplify

\frac{1}{3} + \frac{1}{5} : \frac{8}{15}

= \frac{8}{15}

Graph

Popular Examples

integral from 0 to 1 of-x^2+2

\int_{0}^{1} - x^{2} + 2 d x

integral from 0 to pi of θ

\int_{0}^{π} θ d θ

integral from 0 to pi/2 of (1+cos(x))^2

\int_{0}^{\frac{π}{2}} (1 + cos (x))^{2} d x

integral from 1 to 2 of 7

\int_{1}^{2} 7 d x

integral from 1 to 4 of (x^2+1)^2

\int_{1}^{4} (x^{2} + 1)^{2} d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 1 of x^2+x^4 ?
The integral from 0 to 1 of x^2+x^4 is 8/15