What is the integral from 2 to 5 of k/(x^3) ?

The integral from 2 to 5 of k/(x^3) is (21k)/(200)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 2 to 5 of k/(x^3)

\int_{2}^{5} \frac{k}{x ^{3}} d x

\frac{21 k}{200}

Solution steps

\int_{2}^{5} \frac{k}{x ^{3}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= k \cdot \int_{2}^{5} \frac{1}{x ^{3}} d x

Apply the Power Rule

: [- \frac{1}{2 x ^{2}}]_{2}^{5}

= k [- \frac{1}{2 x ^{2}}]_{2}^{5}

Compute the boundaries:

\frac{21}{200}

= k \frac{21}{200}

Simplify

= \frac{21 k}{200}

\int_{0}^{2} (x - x^{2}) d x

\int_{0}^{2 x^{2}} t ln (t) d t

\int_{1}^{8} 3 x - 1 d x

\int_{1}^{8} 1 + x^{3} d x

\int_{\frac{x}{2}}^{2 x - \frac{x ^{2}}{4}} 1

What is the integral from 2 to 5 of k/(x^3) ?
The integral from 2 to 5 of k/(x^3) is (21k)/(200)