What is the integral from 4.2 to 9.9 of 12x^2-6x+4/x ?

The integral from 4.2 to 9.9 of 12x^2-6x+4/x is 3347.16380…

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integral from 4.2 to 9.9 of 12x^2-6x+4/x

\int_{4.2}^{9.9} 12 x^{2} - 6 x + \frac{4}{x} d x

3347.16380 \dots

Solution steps

\int_{4.2}^{9.9} 12 x^{2} - 6 x + \frac{4}{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{4.2}^{9.9} 12 x^{2} d x - \int_{4.2}^{9.9} 6 x d x + \int_{4.2}^{9.9} \frac{4}{x} d x

\int_{4.2}^{9.9} 12 x^{2} d x = 3584.844

\int_{4.2}^{9.9} 6 x d x = 241.11

\int_{4.2}^{9.9} \frac{4}{x} d x = 3.42980 \dots

= 3584.844 - 241.11 + 3.42980 \dots

Simplify

= 3347.16380 \dots

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What is the integral from 4.2 to 9.9 of 12x^2-6x+4/x ?
The integral from 4.2 to 9.9 of 12x^2-6x+4/x is 3347.16380…