What is the integral from 0 to x of sin(y) ?

The integral from 0 to x of sin(y) is -cos(x)+1

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integral from 0 to x of sin(y)

\int_{0}^{x} sin (y) d y

- cos (x) + 1

Solution steps

\int_{0}^{x} sin (y) d y

Use the common integral:

\int sin (y) d y = - cos (y)

= [- cos (y)]_{0}^{x}

Compute the boundaries:

- cos (x) + 1

= - cos (x) + 1

\int_{0}^{x} \frac{8}{81} x y d y

\int_{- e - 1}^{- 2} \frac{1}{x + 1} d x

\int_{0}^{π} 6 sin (t) d t

\int_{- 2}^{1} x^{2} - 2 x + 3 d x

\int_{1}^{2^{337}} \frac{1}{2 x} d x

What is the integral from 0 to x of sin(y) ?
The integral from 0 to x of sin(y) is -cos(x)+1