What is the integral from 0 to 12 of pi(sqrt(x))^2 ?

The integral from 0 to 12 of pi(sqrt(x))^2 is pi72

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integral from 0 to 12 of pi(sqrt(x))^2

\int_{0}^{12} π (x)^{2} d x

π 72

Decimal

226.19467 \dots

Solution steps

\int_{0}^{12} π (x)^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= π \cdot \int_{0}^{12} (x)^{2} d x

Simplify

(x)^{2} : x

= π \cdot \int_{0}^{12} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{12}

= π [\frac{x ^{2}}{2}]_{0}^{12}

Compute the boundaries:

72

= π 72

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What is the integral from 0 to 12 of pi(sqrt(x))^2 ?
The integral from 0 to 12 of pi(sqrt(x))^2 is pi72