What is the integral from-1 to 1 of x^3+x^5+7x^9 ?

The integral from-1 to 1 of x^3+x^5+7x^9 is 0

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integral from-1 to 1 of x^3+x^5+7x^9

\int_{- 1}^{1} x^{3} + x^{5} + 7 x^{9} d x

0

Solution steps

\int_{- 1}^{1} x^{3} + x^{5} + 7 x^{9} d x

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

x^{3} + x^{5} + 7 x^{9} :

Odd

= 0

\int_{0}^{16} x - 3 d x

\int_{1}^{3} (x^{2} - 6 x + 5) d x

\int_{2}^{4} 3 x - 1 + 2 x^{2} d x

\int_{0}^{2} 5 - t^{3} d t

\int_{0}^{2} \frac{3}{x + 4} d x

What is the integral from-1 to 1 of x^3+x^5+7x^9 ?
The integral from-1 to 1 of x^3+x^5+7x^9 is 0