What is the integral from 6 to 8 of 4-10e^{-0.2x} ?

The integral from 6 to 8 of 4-10e^{-0.2x} is 3.03511…

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integral from 6 to 8 of 4-10e^{-0.2x}

\int_{6}^{8} 4 - 10 e^{- 0.2 x} d x

3.03511 \dots

Solution steps

\int_{6}^{8} 4 - 10 e^{- 0.2 x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{6}^{8} 4 d x - \int_{6}^{8} 10 e^{- 0.2 x} d x

\int_{6}^{8} 4 d x = 8

\int_{6}^{8} 10 e^{- 0.2 x} d x = 4.96488 \dots

= 8 - 4.96488 \dots

Simplify

= 3.03511 \dots

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What is the integral from 6 to 8 of 4-10e^{-0.2x} ?
The integral from 6 to 8 of 4-10e^{-0.2x} is 3.03511…