What is the integral from 1 to 3 of-x^2 ?

The integral from 1 to 3 of-x^2 is -26/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 3 of-x^2

\int_{1}^{3} - x^{2} d x

- \frac{26}{3}

Decimal

- 8.66666 \dots

Solution steps

\int_{1}^{3} - x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int_{1}^{3} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{1}^{3}

= - [\frac{x ^{3}}{3}]_{1}^{3}

Compute the boundaries:

\frac{26}{3}

= - \frac{26}{3}

\int_{1}^{1.5} 1 d x

\int_{0}^{4} (4 - x^{2})^{2} d x

\int_{1}^{\infty} \frac{c}{x ^{4}} d x

\int_{1}^{3} (x^{2} - 2 x - 3) d x

\int_{y^{3}}^{y} (1 - y^{2})^{8} d y

What is the integral from 1 to 3 of-x^2 ?
The integral from 1 to 3 of-x^2 is -26/3