What is the integral from-2 to 1 of e^x ?

The integral from-2 to 1 of e^x is e-1/(e^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-2 to 1 of e^x

\int_{- 2}^{1} e^{x} d x

e - \frac{1}{e ^{2}}

Decimal

2.58294 \dots

Solution steps

\int_{- 2}^{1} e^{x} d x

Use the common integral:

\int e^{x} d x = e^{x}

= [e^{x}]_{- 2}^{1}

Compute the boundaries:

e - \frac{1}{e ^{2}}

= e - \frac{1}{e ^{2}}

\int_{1}^{3} x + 1 d x

\int_{- 1}^{4} (3 x - 4) (x + 3) d x

\int_{3}^{6} x y d x

\int_{1}^{2} (x^{2} - x) d x

\int_{- 2}^{2} x^{3} cos (\frac{x}{2}) + \frac{1}{2} 4 - x^{2} d x

What is the integral from-2 to 1 of e^x ?
The integral from-2 to 1 of e^x is e-1/(e^2)