What is the integral from-2 to 2 of (x^3)/(1+x^2) ?

The integral from-2 to 2 of (x^3)/(1+x^2) is 0

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integral from-2 to 2 of (x^3)/(1+x^2)

\int_{- 2}^{2} \frac{x ^{3}}{1 + x ^{2}} d x

0

Solution steps

\int_{- 2}^{2} \frac{x ^{3}}{1 + x ^{2}} d x

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

\frac{x ^{3}}{1 + x ^{2}} :

Odd

= 0

\int_{0}^{2} 2 x - 4 d x

\int_{0}^{l n (x)} y e^{z} d z

\int_{2}^{10} \frac{1}{12} d x

\int_{- 5}^{3} \frac{x ^{3} - 2 x + 45}{2} d x

\int_{1}^{2} 2 x e^{4 x^{2} + 2} d x

What is the integral from-2 to 2 of (x^3)/(1+x^2) ?
The integral from-2 to 2 of (x^3)/(1+x^2) is 0