What is the integral from 0 to infinity of 1/(2x^2) ?

The integral from 0 to infinity of 1/(2x^2) is diverges

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integral from 0 to infinity of 1/(2x^2)

\int_{0}^{\infty} \frac{1}{2 x ^{2}} d x

diverges

Solution steps

\int_{0}^{\infty} \frac{1}{2 x ^{2}} d x

Compute the indefinite integral:

\int \frac{1}{2 x ^{2}} d x = - \frac{1}{2 x} + C

Compute the boundaries:

\int_{0}^{\infty} \frac{1}{2 x ^{2}} d x =

diverges

= diverges

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What is the integral from 0 to infinity of 1/(2x^2) ?
The integral from 0 to infinity of 1/(2x^2) is diverges