What is the integral from-1 to 1 of x^{99} ?

The integral from-1 to 1 of x^{99} is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-1 to 1 of x^{99}

\int_{- 1}^{1} x^{99} d x

0

Solution steps

\int_{- 1}^{1} x^{99} d x

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

x^{99} :

Odd

= 0

\int_{0}^{2} x x^{2} + 4 d x

\int_{0}^{2} \frac{x}{1 + x} d x

\int_{0}^{20} \frac{x}{9 + 2 x} d x

\int_{π}^{2 π} cos^{2} (θ) d θ

\int_{0}^{1} 2 π x (6 x (x - 1)^{2}) d x

What is the integral from-1 to 1 of x^{99} ?
The integral from-1 to 1 of x^{99} is 0