What is the integral from 1 to 5 of (9x)^3 ?

The integral from 1 to 5 of (9x)^3 is 113724

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 5 of (9x)^3

\int_{1}^{5} (9 x)^{3} d x

113724

Solution steps

\int_{1}^{5} (9 x)^{3} d x

Simplify

(9 x)^{3} : 729 x^{3}

= \int_{1}^{5} 729 x^{3} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 729 \cdot \int_{1}^{5} x^{3} d x

Apply the Power Rule

: [\frac{x ^{4}}{4}]_{1}^{5}

= 729 [\frac{x ^{4}}{4}]_{1}^{5}

Compute the boundaries:

156

= 729 \cdot 156

Simplify

= 113724

\int_{- 2}^{2} (3 - ∣ x ∣) d x

\int_{1}^{2} \frac{x ^{5} + 7 x ^{2}}{x ^{2}} d x

\int_{π}^{x} \frac{cos ( y )}{y} d y

\int_{- 1}^{1} \frac{5}{3 + x ^{2}} d x

\int_{1}^{2} \frac{x}{x + 1} d x

What is the integral from 1 to 5 of (9x)^3 ?
The integral from 1 to 5 of (9x)^3 is 113724