What is the integral from 1 to x^2 of cos(t) ?

The integral from 1 to x^2 of cos(t) is sin(x^2)-sin(1)

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integral from 1 to x^2 of cos(t)

\int_{1}^{x^{2}} cos (t) d t

sin (x^{2}) - sin (1)

Solution steps

\int_{1}^{x^{2}} cos (t) d t

Use the common integral:

\int cos (t) d t = sin (t)

= [sin (t)]_{1}^{x^{2}}

Compute the boundaries:

sin (x^{2}) - sin (1)

= sin (x^{2}) - sin (1)

\int_{0}^{1} x^{2} (4 - x^{2}) d x

\int_{0}^{3} \frac{1}{2} x - 1 d x

\int_{1}^{11} \frac{4 ( ln ( x ) ) ^{3}}{x} d x

\int_{0}^{3} \frac{sin ( x )}{x} d x

\int_{0}^{3} (x^{2} - 3 x + 2) d x

What is the integral from 1 to x^2 of cos(t) ?
The integral from 1 to x^2 of cos(t) is sin(x^2)-sin(1)