What is the integral from 0 to 19pi of sin(x) ?

The integral from 0 to 19pi of sin(x) is 2

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integral from 0 to 19pi of sin(x)

\int_{0}^{19 π} sin (x) d x

2

Solution steps

\int_{0}^{19 π} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= [- cos (x)]_{0}^{19 π}

Compute the boundaries:

2

= 2

\int_{2}^{x y} 24 x y d z

\int_{- 3}^{3} 4 x^{2} d x

\int_{- 2}^{3} (x + 4) - (x^{2} - 2) d x

\int_{0}^{6} e^{x^{2}} d x

\int_{\frac{π}{6}}^{\frac{π}{2}} 2 sin (x) d x

What is the integral from 0 to 19pi of sin(x) ?
The integral from 0 to 19pi of sin(x) is 2