What is the integral from 1 to 3 of 2^{3x} ?

The integral from 1 to 3 of 2^{3x} is (168)/(ln(2))

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integral from 1 to 3 of 2^{3x}

\int_{1}^{3} 2^{3 x} d x

\frac{168}{ln ( 2 )}

Decimal

242.37276 \dots

Solution steps

\int_{1}^{3} 2^{3 x} d x

Simplify

2^{3 x} : 8^{x}

= \int_{1}^{3} 8^{x} d x

\int a^{x} d x = \frac{a ^{x}}{ln a}

= [\frac{8 ^{x}}{ln ( 8 )}]_{1}^{3}

Simplify

ln (8) : 3 ln (2)

= [\frac{8 ^{x}}{3 ln ( 2 )}]_{1}^{3}

Compute the boundaries:

\frac{168}{ln ( 2 )}

= \frac{168}{ln ( 2 )}

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What is the integral from 1 to 3 of 2^{3x} ?
The integral from 1 to 3 of 2^{3x} is (168)/(ln(2))