What is the integral from 0 to b of 1/(x^2) ?

The integral from 0 to b of 1/(x^2) is diverges

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integral from 0 to b of 1/(x^2)

\int_{0}^{b} \frac{1}{x ^{2}} d x

diverges

Solution steps

\int_{0}^{b} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{0}^{b}

= [- \frac{1}{x}]_{0}^{b}

Compute the boundaries:

diverges

= diverges

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\int_{0}^{2} 4 x^{2} e^{2 x} d x

\int_{0}^{2} 2 y 4 - y^{2} d y

\int_{0}^{2} \frac{1}{( 1 + x ) ^{2}} d x

\int_{1}^{2} (3 x^{2} - 5 x) d x

What is the integral from 0 to b of 1/(x^2) ?
The integral from 0 to b of 1/(x^2) is diverges