What is the integral from 2pi to 5pi of |sin(t)| ?

The integral from 2pi to 5pi of |sin(t)| is 6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 2pi to 5pi of |sin(t)|

\int_{2 π}^{5 π} ∣ sin (t) ∣ d t

6

Solution steps

\int_{2 π}^{5 π} ∣ sin (t) ∣ d t

Eliminate Absolutes

= \int_{2 π}^{3 π} sin (t) d t + \int_{3 π}^{4 π} - sin (t) d t + \int_{4 π}^{5 π} sin (t) d t

\int_{2 π}^{3 π} sin (t) d t = 2

\int_{3 π}^{4 π} - sin (t) d t = 2

\int_{4 π}^{5 π} sin (t) d t = 2

= 2 + 2 + 2

Simplify

= 6

\int_{1}^{4} 2 u d u

\int_{0}^{2} ∣ 2 x - 3 ∣ d x

\int_{m}^{\infty} \frac{1}{n ^{6.63}} d n

\int_{0}^{t} e^{t - v} d v

\int_{0}^{\frac{π}{4}} 4 sec^{2} (t) d t

What is the integral from 2pi to 5pi of |sin(t)| ?
The integral from 2pi to 5pi of |sin(t)| is 6