What is the integral from 0 to 1 of (2x)/3 ?

The integral from 0 to 1 of (2x)/3 is 1/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 1 of (2x)/3

\int_{0}^{1} \frac{2 x}{3} d x

\frac{1}{3}

Decimal

0.33333 \dots

Solution steps

\int_{0}^{1} \frac{2 x}{3} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{2}{3} \cdot \int_{0}^{1} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{1}

= \frac{2}{3} [\frac{x ^{2}}{2}]_{0}^{1}

Compute the boundaries:

\frac{1}{2}

= \frac{2}{3} \cdot \frac{1}{2}

Simplify

= \frac{1}{3}

\int_{- 2}^{20} ∣ x - 10 ∣ d x

\int_{0}^{3} \frac{1}{( x - 3 ) ^{2}} d x

\int_{0}^{1} x^{4} x^{3} d x

\int_{3}^{\infty} t e^{- s t} d t

\int_{- 4}^{4} x^{2} - 3 d x

What is the integral from 0 to 1 of (2x)/3 ?
The integral from 0 to 1 of (2x)/3 is 1/3