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Popular >

integral from 0 to 4 of (x^2-4)

Solution

\int_{0}^{4} (x^{2} - 4) d x

Solution

\frac{16}{3}

+1

Decimal

5.33333 \dots

Solution steps

\int_{0}^{4} x^{2} - 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} x^{2} d x - \int_{0}^{4} 4 d x

\int_{0}^{4} x^{2} d x = \frac{64}{3}

\int_{0}^{4} 4 d x = 16

= \frac{64}{3} - 16

Simplify

\frac{64}{3} - 16 : \frac{16}{3}

= \frac{16}{3}

Graph

Popular Examples

integral from 2 to infinity of 1/(ln(n))

\int_{2}^{\infty} \frac{1}{ln ( n )}

integral from 0 to pi/4 of 1/(x^2+1)

\int_{0}^{\frac{π}{4}} \frac{1}{x ^{2} + 1} d x

integral from 7 to 9 of x^2+2x-6

\int_{7}^{9} x^{2} + 2 x - 6 d x

integral from 0 to a of 2xsqrt(a^2-x^2)

\int_{0}^{a} 2 x a^{2} - x^{2} d x

integral from 7 to 9 of x^2+2x-2

\int_{7}^{9} x^{2} + 2 x - 2 d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 4 of (x^2-4) ?
The integral from 0 to 4 of (x^2-4) is 16/3