What is the integral from 2 to 3 of e^{x-2}-e ?

The integral from 2 to 3 of e^{x-2}-e is (e^3-e^2)/(e^2)-e

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integral from 2 to 3 of e^{x-2}-e

\int_{2}^{3} e^{x - 2} - e d x

\frac{e ^{3} - e ^{2}}{e ^{2}} - e

Decimal

- 1

Solution steps

\int_{2}^{3} e^{x - 2} - e d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{2}^{3} e^{x - 2} d x - \int_{2}^{3} e d x

\int_{2}^{3} e^{x - 2} d x = \frac{e ^{3} - e ^{2}}{e ^{2}}

\int_{2}^{3} e d x = e

= \frac{e ^{3} - e ^{2}}{e ^{2}} - e

\int_{0}^{3} t 1 + t^{2} d t

\int_{\infty}^{0} e^{x} d x

\int_{2}^{3} \frac{x ^{2} - 4}{x} d x

\int_{1}^{2} (3 x - 1)^{3} d x

\int_{- 1}^{1} 3 t d t

What is the integral from 2 to 3 of e^{x-2}-e ?
The integral from 2 to 3 of e^{x-2}-e is (e^3-e^2)/(e^2)-e