What is the integral from 1 to 4 of (6x^2-2x) ?

The integral from 1 to 4 of (6x^2-2x) is 111

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integral from 1 to 4 of (6x^2-2x)

\int_{1}^{4} (6 x^{2} - 2 x) d x

111

Solution steps

\int_{1}^{4} 6 x^{2} - 2 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{4} 6 x^{2} d x - \int_{1}^{4} 2 x d x

\int_{1}^{4} 6 x^{2} d x = 126

\int_{1}^{4} 2 x d x = 15

= 126 - 15

Simplify

= 111

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What is the integral from 1 to 4 of (6x^2-2x) ?
The integral from 1 to 4 of (6x^2-2x) is 111