What is the integral from-pi/2 to pi of 8cos(x) ?

The integral from-pi/2 to pi of 8cos(x) is 8

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integral from-pi/2 to pi of 8cos(x)

\int_{- \frac{π}{2}}^{π} 8 cos (x) d x

8

Solution steps

\int_{- \frac{π}{2}}^{π} 8 cos (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 8 \cdot \int_{- \frac{π}{2}}^{π} cos (x) d x

Use the common integral:

\int cos (x) d x = sin (x)

= 8 [sin (x)]_{- \frac{π}{2}}^{π}

Compute the boundaries:

1

= 8 \cdot 1

Simplify

= 8

\int_{5}^{- 5} (3 r + 2)^{2} d r

\int_{0}^{π} \frac{1 - cos ( 2 x )}{2} d x

\int_{- 5}^{\infty} e^{- 0.2 x} d x

\int_{1}^{\infty} x^{- \frac{1}{1}} d x

\int_{0}^{5} (2 x - 5) d x

What is the integral from-pi/2 to pi of 8cos(x) ?
The integral from-pi/2 to pi of 8cos(x) is 8