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Popular >

integral from 0 to 1 of-x^3+x

Solution

\int_{0}^{1} - x^{3} + x d x

Solution

\frac{1}{4}

+1

Decimal

0.25

Solution steps

\int_{0}^{1} - x^{3} + x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{0}^{1} x^{3} d x + \int_{0}^{1} x d x

\int_{0}^{1} x^{3} d x = \frac{1}{4}

\int_{0}^{1} x d x = \frac{1}{2}

= - \frac{1}{4} + \frac{1}{2}

Simplify

- \frac{1}{4} + \frac{1}{2} : \frac{1}{4}

= \frac{1}{4}

Graph

Popular Examples

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\int_{0}^{1} e^{t} e^{e^{t}} d t

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\int_{0}^{3} (\frac{2}{x + 1})^{2} d x

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\int_{- 2}^{2} x 1 - x^{2} d x

integral from-3 to 3 of 8x^3

\int_{- 3}^{3} 8 x^{3} d x

integral from 1 to 5 of ln(3x)-ln(x)

\int_{1}^{5} ln (3 x) - ln (x) d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 1 of-x^3+x ?
The integral from 0 to 1 of-x^3+x is 1/4