What is the integral from 0 to 2 of (e^x) ?

The integral from 0 to 2 of (e^x) is e^2-1

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integral from 0 to 2 of (e^x)

\int_{0}^{2} (e^{x}) d x

e^{2} - 1

Decimal

6.38905 \dots

Solution steps

\int_{0}^{2} e^{x} d x

Use the common integral:

\int e^{x} d x = e^{x}

= [e^{x}]_{0}^{2}

Compute the boundaries:

e^{2} - 1

= e^{2} - 1

\int_{0}^{3} 4 x (x - 6) d x

\int_{0}^{5} x - 3 d x

\int_{0}^{2} (6 x - 9) (8 x^{2} + 2) d x

\int_{0}^{3} \frac{e ^{x}}{10 + e ^{x}} d x

\int_{2}^{6} \frac{5}{x} d x

What is the integral from 0 to 2 of (e^x) ?
The integral from 0 to 2 of (e^x) is e^2-1