What is the integral from-4 to 4 of (-1/5 x^3+5x) ?

The integral from-4 to 4 of (-1/5 x^3+5x) is 0

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integral from-4 to 4 of (-1/5 x^3+5x)

\int_{- 4}^{4} (- \frac{1}{5} x^{3} + 5 x) d x

0

Solution steps

\int_{- 4}^{4} - \frac{1}{5} x^{3} + 5 x d x

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

- \frac{1}{5} x^{3} + 5 x :

Odd

= 0

\int_{1}^{10} (\frac{1}{x}) d x

\int_{0}^{b} 4 e^{x} d x

\int_{0}^{5} ∣ x - 1 ∣ d x

\int_{0}^{6} e^{t} - e^{- t} d t

\int_{0}^{6} (x) d x

What is the integral from-4 to 4 of (-1/5 x^3+5x) ?
The integral from-4 to 4 of (-1/5 x^3+5x) is 0