What is the derivative of (1-x^2/(1+x^2)) ?

The derivative of (1-x^2/(1+x^2)) is -(4x)/((1+x^2)^2)

What is the first derivative of (1-x^2/(1+x^2)) ?

The first derivative of (1-x^2/(1+x^2)) is -(4x)/((1+x^2)^2)

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\frac{d}{d x} (\frac{1 - x ^{2}}{1 + x ^{2}})

- \frac{4 x}{( 1 + x ^{2} ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{1 - x ^{2}}{1 + x ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 1 - x ^{2} ) ( 1 + x ^{2} ) - \frac{d}{d x} ( 1 + x ^{2} ) ( 1 - x ^{2} )}{( 1 + x ^{2} ) ^{2}}

\frac{d}{d x} (1 - x^{2}) = - 2 x

\frac{d}{d x} (1 + x^{2}) = 2 x

= \frac{( - 2 x ) ( 1 + x ^{2} ) - 2 x ( 1 - x ^{2} )}{( 1 + x ^{2} ) ^{2}}

Simplify

\frac{( - 2 x ) ( 1 + x ^{2} ) - 2 x ( 1 - x ^{2} )}{( 1 + x ^{2} ) ^{2}} : - \frac{4 x}{( 1 + x ^{2} ) ^{2}}

= - \frac{4 x}{( 1 + x ^{2} ) ^{2}}

\frac{d y}{d x} = - 4 y

x^{4} - 8 x^{2} + 16

x^{2} + 2 x

\int \frac{1}{9 e ^{- 2 x} - 1} d x

f (x) = x^{3}, at x = - 1

What is the derivative of (1-x^2/(1+x^2)) ?
The derivative of (1-x^2/(1+x^2)) is -(4x)/((1+x^2)^2)
What is the first derivative of (1-x^2/(1+x^2)) ?
The first derivative of (1-x^2/(1+x^2)) is -(4x)/((1+x^2)^2)