What is the integral from 1 to 2 of 1/(x^7) ?

The integral from 1 to 2 of 1/(x^7) is 21/128

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integral from 1 to 2 of 1/(x^7)

\int_{1}^{2} \frac{1}{x ^{7}} d x

\frac{21}{128}

Decimal

0.1640625

Solution steps

\int_{1}^{2} \frac{1}{x ^{7}} d x

Apply the Power Rule

: [- \frac{1}{6 x ^{6}}]_{1}^{2}

= [- \frac{1}{6 x ^{6}}]_{1}^{2}

Compute the boundaries:

\frac{21}{128}

= \frac{21}{128}

\int_{0}^{2} x (x - 1) d x

\int_{0}^{\frac{π}{4}} sin^{7} (y) d y

\int_{0}^{1} 17 x e^{x} d x

\int_{0}^{1} \frac{x}{( x + 3 ) ^{2}} d x

\int_{0}^{2 π} (cos^{2} (θ)) d θ

What is the integral from 1 to 2 of 1/(x^7) ?
The integral from 1 to 2 of 1/(x^7) is 21/128