What is the integral from 0 to 1 of 484t^{10}+9t^8 ?

The integral from 0 to 1 of 484t^{10}+9t^8 is 45

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integral from 0 to 1 of 484t^{10}+9t^8

\int_{0}^{1} 484 t^{10} + 9 t^{8} d t

45

Solution steps

\int_{0}^{1} 484 t^{10} + 9 t^{8} d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} 484 t^{10} d t + \int_{0}^{1} 9 t^{8} d t

\int_{0}^{1} 484 t^{10} d t = 44

\int_{0}^{1} 9 t^{8} d t = 1

= 44 + 1

Simplify

= 45

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What is the integral from 0 to 1 of 484t^{10}+9t^8 ?
The integral from 0 to 1 of 484t^{10}+9t^8 is 45