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Popular >

integral from 0 to 1 of (6-9x^2)

Solution

\int_{0}^{1} (6 - 9 x^{2}) d x

Solution

3

Solution steps

\int_{0}^{1} 6 - 9 x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} 6 d x - \int_{0}^{1} 9 x^{2} d x

\int_{0}^{1} 6 d x = 6

\int_{0}^{1} 9 x^{2} d x = 3

= 6 - 3

Simplify

= 3

Popular Examples

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\int_{0}^{4} (3 x + x) d x

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\int_{3}^{7} t^{5} ln (t) d t

integral from 0 to 2 of (x^2)/(x^3+3)

\int_{0}^{2} \frac{x ^{2}}{x ^{3} + 3} d x

integral from 0 to 1 of xsinh(x)

\int_{0}^{1} x sinh (x) d x

integral from 0 to 3 of x^2-3

\int_{0}^{3} x^{2} - 3 d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 1 of (6-9x^2) ?
The integral from 0 to 1 of (6-9x^2) is 3