What is the integral from 2 to x of t^3 ?

The integral from 2 to x of t^3 is (x^4)/4-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 2 to x of t^3

\int_{2}^{x} t^{3} d t

\frac{x ^{4}}{4} - 4

Solution steps

\int_{2}^{x} t^{3} d t

Apply the Power Rule

: [\frac{t ^{4}}{4}]_{2}^{x}

= [\frac{t ^{4}}{4}]_{2}^{x}

Compute the boundaries:

\frac{x ^{4}}{4} - 4

= \frac{x ^{4}}{4} - 4

\int_{1}^{2} \frac{5}{x ^{6}} d x

\int_{- 1}^{1} sinh (x) d x

\int_{- \infty}^{0} x sin (x) d x

\int_{0}^{1} (7 x^{2} - 4 x + 3) d x

\int_{0}^{\frac{π}{2}} (x cos (x)) d x

What is the integral from 2 to x of t^3 ?
The integral from 2 to x of t^3 is (x^4)/4-4